In the figure, given above, AB=AD, BC=DC. Find :- Angle ABC
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Angle ABC=116°
See the image attached
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In ∆ ABD,
54 + x + x = 180° (sum of all angles in a triangle is 180°)
x = 63°
In ∆ DBC,
116° + y + y = 180°
y = 32°
∠ ABC = x + y = 63° + 32° = 95°
=> ∠ ABC = 95°
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