Question

In the figure given above, AB is parallel to DC, BC = AD = 13 cm, AB = 22 cm and DC = 12 cm. Calculate the height of the trapezium ABCD. ​

Answer 1

Answer:

let the point on which DandC cut be L and M respectively.

by phythagores

{13}^{2} = {5}^{2} + {h}^{2}13

2

=5

2

+h

2

169= 25+h^2

169-25=h^2

h=

\sqrt{144}

root 144

=12

therefor height is equal to 12 .

Answer 2

Answer:

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