Question

In the figure given above
ABCD is a square of side 50 m. Points
P, Q, R, S are midpoints of side AB, side BC, side CD, side AD
respectively. Find area of shaded region.​

Answer 1

Step-by-step explanation:

Hope it helps you. Maharashtra board exam Q4 3

Answer 2

Step-by-step explanation:

Area of square = (50)a sq = 2500

Area of 4 corner =

$4 \times \frac{1}{4} \pi {}^{2}$

$= \frac{22}{7} \times 25m {}^{2} \times 25m {}^{2}$

= 1,964.28

Area of shaded portion = Area of square - Area of 4 corner = 2500 - 1964.28

535.72m sq

I hope this may help you