Question

In the figure given above, BC = 5 cm, angle B = 90°, AB = 5AE, CD = 2AE and AC = ED. Calculate the lengths of EA, CD, AB and AC ​

Answer 1

Answer:

Answer:

BC=5cm

AE=x

AB=5AE=5x => BE=5x-x=4x

CD=2x

AB²+BC²=AC² => (5x)²+5²=Ac2

BE²+BD²=ED² => (4x)²+(5+2x)²=ED²

AC=ED =>  

(5x)²+5²=(4x)²+(5+2x)

25x²+25= 16x²+25+20x+4x²

5x²-20x=0

x(x-4)=0

x=4 cm

EA= 4 cm

CD= 2*4 cm= 8 cm

AB= 5*4 cm= 20 cm

AC= √(5*4)²+25= √425=5√17

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Answer 2

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