Question

in the figure given above quadrilateral ABCD is a square of side 50 points P Q R S are midpoints of side a b side BC side CD side a d respectively find area of shaded region​

Answer 1

Answer:

here is solution for ur question

Answer 2

Area of shaded region​ = 536.5 sq. point.

Given:

• Quadrilateral ABCD is a square of side 50 points.
• P Q R S are midpoints of side AB side BC side CD side AD respectively.

To find:

• Area of shaded region​.

Formula used:

Area of square= (side)²

Area of circle = $\pi$× (Radius)²

Explanation:

• P is the mid point of side AB

             AB = 50 Points

      Hence PA=PB= $\frac{AB}{2}$ = $\frac{50}{2}$ =25 points.

• In same way Q is the mid point of side BC

                  BQ=CQ = $\frac{BC}{2}$ = $\frac{50}{2}$ =25 points

• Similar way CR=DR = 25 points.

                   AS=DS=25 points

• In figure there are four quadrupled circle which forms a full circle of 25 point.

• So Area of circle = $\pi$× (Radius)²

                                    =  $\pi$× (25)²

                                     = 3.14 × 625

                                     = 1963.5 sq. point.

Side of the square = 50 point.

• And area of square = (side)²

                                 = 50² = 2500 sq. point.

• From the figure If we subtract area of square and area of circle

       To find shaded area :

• Area of shaded region​ = 2500 - 1963.5

                                       = 536.5 sq. point.

Area of shaded region​ = 536.5 sq. point.

To learn more....

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