Question

In the figure given alongside Angle B = 30 degree angle C = 40 degree and the bisector of angle A meets BC at D show that B D greater than a d

Answer 1

Answer:

If Angle B= 30 and C= 40 then A = 110

i.e. 1/2 A =110/2=55

angle 1/2A>B

i.e. BD>AD  [From the theorem, if a angle is greater than one there opposite sides will also follow the same.]

Answer 2

Step by step explanation:

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