Question

in the figure given alongside find angle ACD and angle AeD

Answer 1

Step-by-step explanation:

angle ABC =180-45+25

= 180-70=110

Let angle DCE=X

X+110=180 (Angle sum property)

x=70

Angle AED=180-70=110

HOPE THIS HELPS YOU!!!!!!!

Answer 2

The measure of angle ACD and AED is 70° and 110° respectively.

Given:

two triangles as shown in the figure above

To Find:

the measures of angles ACD and AED

Solution:

In triangle ABC,

∠ABC + ∠BCA + ∠CAB = 180°

⇒ 25 + 45 + ∠BCA = 180

∠BCA = 180 - 70

∠BCA = 110

Now, since BCD is a straight line,

∠BCA + ∠ECD = 180°

⇒ ∠ECD = 180 - 110

∠ECD = 70°

Now, in triangle ECD,

∠CED + ∠EDC + ∠DCE = 180°

⇒ 40 + 70 + ∠CED = 180

∠CED = 180 - 110

∠CED = 70

Further, AEC is a straight line,

∠CED + ∠AED = 180°

⇒ ∠AED = 180 - 70

∠AED = 110°

Thus, the measure of angle ACD and AED is 70° and 110° respectively.

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