In the figure given below, AB = AC and D is the mid point of BC.
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Step-by-step explanation:
AB=AC
P is midpoint
BD=DC→(i)
inΔABD&ΔACD
AB=AC(given)
BD=DCfromeq(i)
AD=ADcommon
fromSSSrule
ΔADB≅ΔADC
∠B=∠C(CPCT)
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