In the figure given below AB and CD are chords and PQ is the diameter. If AEQ=DEQ, prove that AB=CD.
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Step-by-step explanation:
Draw a circle of radius r and draw diameters AD and BC and then join AB and CD as shown in the figure.
In △AOB and △COD ,
AO=DO (radius)
BO=CO (radius of circle)
∠AOB=∠DOC (opposite angles)
Hence, △AOB≅△DOC (by SAS)
⇒AB≅CD {By c.p.c.t.}
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