Math, asked by pdyes, 2 days ago

In the figure given below AB and CD are chords and PQ is the diameter. If AEQ=DEQ, prove that AB=CD.​

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Answered by sarthakdadu07
1

Answer:

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Step-by-step explanation:

Draw a circle of radius r and draw diameters AD and BC and then join AB and CD as shown in the figure.

In △AOB and △COD ,

AO=DO  (radius)

BO=CO (radius of circle)

∠AOB=∠DOC (opposite angles)

Hence, △AOB≅△DOC (by SAS)

⇒AB≅CD  {By c.p.c.t.}

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