In the figure given below, AB = CD and AD = CB. Prove that ∠BCD = ∠DAB.
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GIVEN :
➡AB = CD and AD = CB
TO PROVE :
➡ ∠BCD = ∠DAB
PROOF :
⤵
In ΔABD & ΔDCB,
AB = CD (given)
AD = CB (given)
DB = DB (common)
So, ΔABD ≅ ΔDCB ( By SSS congruency rule)
BY CPCT,
∠BCD = ∠DAB
HENCE, PROVED.
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