Question

In the figure given below, AB=DC and AC=DB. Is ΔABC≅ΔDCB.

Answer 1

Let ABCD IS A parallelogram,

Now, ΔABC and ΔDCB

AB = DC(GIVEN)

AC = BD(GIVEN)

BC = BC (COMMON)


HENCE, ΔABC≅ΔDCB. (By SSS CONGRUENT.

I HOPE ITS HELP YOU DEAR,. THANKS

Answer 2

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SSS congruence rule :

If three sides of one triangle are equal

to the three sides of another triangle ,

then the two triangle are congruent.

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According to the problem given ,

In ∆ABC and ∆DCB ,

AB = DC ( side )

BC = CB ( common side )

AC = DB ( side )

Therefore ,

∆ABC congruent to ∆ DCB

[ SSS congruence rule ]

I hope this helps you.

: )