Question

[ In the figure given below , AB || DC || EF , AD || BE and DE || AF . Prove that the area of DEFH is equal to the area of ABCD.]

Plz ans someone , and the correct one will be marked as brainliest...★♂

Answer 1

Answer: Proved.

Step-by-step explanation: In the given figure, we have

AB || DC and AD || BC, which implies that ABCD is a parallelogram. Similarly, we can show that ADEG and DEFH are also parallelograms.

Here, we will be using the theorem that two parallelograms standing on the same base and lying between the same pair of parallel lines have equal areas.

Now, since parallelograms ABCD and ADEG stand on the same base and lying between the same pair of parallel lines AD and BE. So, we have

Area of ABCD = Area of ADEG.

Again, since parallelograms ADEG and DEFH stand on the same base DE and lying between the same pair of parallel lines DE and AF. So, we have

Area of ADEG = Area of DEFH.

Thus, we arrive at

Area of ABCD = Area of DEFH.

Hence proved.

Answer 2

Answer:

Step-by-step explanation: