Question

in the figure given below AB ll CD if angle EGB =55 and QP perpendicular EF then find angle PQH​

Answer 1

Answer:

angle EGB and angle PQH =55 (alternate exterior angles)

in triangle PHQ, Angles P=90 H=55 ,

so angle PQH =35

Answer 2

=> We know that AB || CD and EF is a transversal,

=> From the figure we know that ∠EGB and ∠GHD are corresponding angles.

So we get,

=> ∠EGB = ∠GHD = 55°

=> From the figure we know that ∠GHD and ∠QHP are vertically opposite angles.

So we get,

=> ∠GHD = ∠QHP = 55°

=> We know that the sum of all the angles in triangle DQHP is 180°.

=> ∠PQH + ∠QHP + ∠QPH = 180°

By substituting the values we get,

=> ∠PQH + 55° + 90° = 180°

On further calculation

=> ∠PQH = 180° – 55° – 90°

By subtraction

=> ∠PQH = 180° – 145° ∠PQH = 35°

• Therefore, ∠PQH = 35°