Question

In the figure given below, AB parallel DE and AC parallel DF, Prove that angle BAC= angle EDF.​

Answer 1

Answer:

Given : AB II DE, AC II DF

(Intersection of AC and DE to be taken as O)

To prove: BAC = EDF

Proof:

BAC = EOC

(Corresponding angles; given that AB II DE)

EOC = EDF

(Corresponding angles; given that AC II DF)

Since,

BAC = EOC

EOC = EDF

Therefore,

BAC = EOC

Hence, proved.

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