Question

In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE? A. 20° C. 40° B. 30° D. 50° 5 ​

Answer 1

Answer:

50

Step-by-step explanation:

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Answer 2

The question is In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE?

It is given that

ABC is a triangle

BC is parallel to AE.

we have to find the value of angle CAE if BC = AC.

The given options are A. 20° C. 40° B. 30° D. 50° 5

From triangle ABC

AC =BC

The angle ABC and the angle CAB are equal to the degree 65. which is 65°.

As we know that the sum of the angle of a triangle is equal to 180°.

Then the angle BCA is equal to 180°-(angle ABC and angle CAB

180°-(65°+65°)

$180 - (65 + 65) \\ 180 - 130 = 50$

The angle BCA is 50°.

It is given that BC is parallel to AE

BC II AE.

The angle BCA is equal to the angle CAE.

the angle CAE.The angle CAE is 50°

the angle CAE.The angle CAE is 50°Hence the final answer to the given question is 50°.

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