In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE? A. 20° C. 40° B. 30° D. 50° 5
Answers
Answer:
50
Step-by-step explanation:
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The question is In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE?
It is given that
ABC is a triangle
BC is parallel to AE.
we have to find the value of angle CAE if BC = AC.
The given options are A. 20° C. 40° B. 30° D. 50° 5
From triangle ABC
AC =BC
The angle ABC and the angle CAB are equal to the degree 65. which is 65°.
As we know that the sum of the angle of a triangle is equal to 180°.
Then the angle BCA is equal to 180°-(angle ABC and angle CAB
180°-(65°+65°)
The angle BCA is 50°.
It is given that BC is parallel to AE
BC II AE.
The angle BCA is equal to the angle CAE.
the angle CAE.The angle CAE is 50°
the angle CAE.The angle CAE is 50°Hence the final answer to the given question is 50°.
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