In the figure given below , ∆ABC is isosceles with AB = AC , <A= 40° and <ABX = 110°.
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∠x+110=180°(linear pair angles are supplementary)
∠x=180-110
∠x=70°
and now to find ∠y
that is
∠y=∠x(if two opposite sides of a triangle are supplementary then their opposite angles are also equal)
∠y=70°
Let's check whether it's correct or not
40+∠y+∠x=180°(sum of all interior angles of a triangle are supplementary)
40+70+70=180
180=180
L.H.S=R.H.S
hence verified
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