In the figure given below , ∠ADC = 130.° Chord BC = Chord BE.
Find ∠ CBE.
[Note : O is not the center ]
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Sagittarius29:
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there it is given that O is the centre of the circle
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In the given figure;
AB and CE are diameters (given)
and BC = BE
Therefore,angle in the semicircle is 90
As CE is also diameter,so
CBE = 90 degrees
AB and CE are diameters (given)
and BC = BE
Therefore,angle in the semicircle is 90
As CE is also diameter,so
CBE = 90 degrees
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