Math, asked by ritu16302, 22 days ago

in the figure given below AN=AC,<BAC=52⁰,<ACK=84⁰,and BCK is a st.line. prove thatNB=NC

Answers

Answered by XxitzAditixX
2

Answer:

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Step-by-step explanation:

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Answered by Shreya762133
0

HII HERE IS YOUR ANSWER

In ∆ANC, angle ANC = angle ACN. (AN=AC)

angle ANC + angle NAC + angle NCA = 180

2angle ANC + 52= 180

2angle ANC = 128/2

angleANC = 64

angle ANC=angle ACN = 64

angle ACK + angle ACN + angle NCB = 180. (linear pair)

84+84+angle NCB =180

angle NCB = 180-148

angle NCB = 32

angle ANC + angle CNB = 180. .(linear pair)

angle CNB = 180 - 64

angle CNB = 116

In ∆BNC,

angle BNC + angle NBC + angle NCB = 180

angle NCB = 32

angle NCB = angle NBC = 32

hence, NB = NC. .(proved)

HOPE IT HELPS YOU.

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