in the figure given below AN=AC,<BAC=52⁰,<ACK=84⁰,and BCK is a st.line. prove thatNB=NC
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HII HERE IS YOUR ANSWER
In ∆ANC, angle ANC = angle ACN. (AN=AC)
angle ANC + angle NAC + angle NCA = 180
2angle ANC + 52= 180
2angle ANC = 128/2
angleANC = 64
angle ANC=angle ACN = 64
angle ACK + angle ACN + angle NCB = 180. (linear pair)
84+84+angle NCB =180
angle NCB = 180-148
angle NCB = 32
angle ANC + angle CNB = 180. .(linear pair)
angle CNB = 180 - 64
angle CNB = 116
In ∆BNC,
angle BNC + angle NBC + angle NCB = 180
angle NCB = 32
angle NCB = angle NBC = 32
hence, NB = NC. .(proved)
HOPE IT HELPS YOU.
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