Question

In the figure given below D, E and F are midpoints of side BC, CA and AB respectively of triangle ABC. If AB =6cm, BC=4.8cm and CA=5.6cm find the perimeter of trapezium FBCE and triangle DEF​

Answer 1

Perimeter of trapezium FBCE = FB + BC + CE + EF

= 3 + 4.8 + 2.8 + 2.4 = 13 cm.

Perimeter of triangle DEF = DE + EF + FD

= 3 + 2.4 + 2.8 = 8.2 cm

or

perimeter of triangle DEF = 1/2 Perimeter of triangle ABC.

=1/2 ( 6 + 4.8 + 5.6 ) =1/2( 16.4 ) = 8.2 cm.

Mid point theorem : The line segment joining the mid points of two sides of a triangle is parallel to the 3rd side and half of it.

Answer 2

Answer:-

Given,

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cm

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABC

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEF

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF⇒EF=21BC[ By mid point theorem ]

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF⇒EF=21BC[ By mid point theorem ]⇒EF=21×4.8=2.4 cm

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF⇒EF=21BC[ By mid point theorem ]⇒EF=21×4.8=2.4 cmSimilarly,

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF⇒EF=21BC[ By mid point theorem ]⇒EF=21×4.8=2.4 cmSimilarly,DE=21AB=21×6=3 cm

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF⇒EF=21BC[ By mid point theorem ]⇒EF=21×4.8=2.4 cmSimilarly,DE=21AB=21×6=3 cmFD=21AC=21×5.6=2.8 cm

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF⇒EF=21BC[ By mid point theorem ]⇒EF=21×4.8=2.4 cmSimilarly,DE=21AB=21×6=3 cmFD=21AC=21×5.6=2.8 cm∴  Perimeter of △DEF=DE+EF+FD

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF⇒EF=21BC[ By mid point theorem ]⇒EF=21×4.8=2.4 cmSimilarly,DE=21AB=21×6=3 cmFD=21AC=21×5.6=2.8 cm∴  Perimeter of △DEF=DE+EF+FD=3+2.4+2.8

Given,AB=6 cm,BC=4.8 cm and CA=5.6 cmD,E and F are the mid points of sides BC,CA and AB of △ABCTo find: The perimeter of △DEFGiven,E and F are the midpoints of sides CA and AB⇒AE=EC  and AF=FD∴ECAE=FBAF⇒EF=21BC[ By mid point theorem ]⇒EF=21×4.8=2.4 cmSimilarly,DE=21AB=21×6=3 cmFD=21AC=21×5.6=2.8 cm∴  Perimeter of △DEF=DE+EF+FD=3+2.4+2.8=8.2 cm

I hope it help you

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