In the figure given below, find angle ABD. Also, find angle ABC, if angle C = 3 angle ABC.
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Answer:
Angle ABD=30°
Angle ABC=20°
Step-by-step explanation:
Given: Angle ADB= 70°
Angle CAB= 100°
To find: Angle ABD
Angle ABC
Angle CAB+Angle DAB=180° (linear pair)
=> 100°+Angle DAB=180°
=> Angle DAB=80°
Let's consider ∆ABD
Angle ABD+Angle DCB+Angle ADB=180° (asp of a ∆)
=> Angle ABD+80°+70°=180°
=> Angle ABD=30°
Let Angle ABC be 'x°'
Then, Angle DCB will be '3x°'
Angle CBD = '30°+x°'
Let's consider ∆CBD
Angle CBD+Angle DAB+Angle CDB=180° (asp of a ∆)
=> 30°+x°+3x°+70°=180°
=> 4x°+100°=180°
=> 4x°=80°
=> x°=20°
Angle ABC=20°
hope it helps!
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