Question

In the figure given below, find the
(a) equivalent capacitance of the network between points A and B.
Given : C1 = C5 = 4 uF, C2 = C3 = C4 = 2 uF.
(b) maximum charge supplied by the battery, and
total energy stored in the network.
1 C2 C3 C4 C5
5V​

Answer 1

Answer:

The equivalent capacitance between points a n b is equal to 2uF.

Answer 2

(a). The equivalent capacitance is 2 μF.

(b). The maximum charge is 10 C.

(c). The total energy stored in the network is 25 J.

Explanation:

Given that,

Capacitance is

$C_{1}=4\ \mu F$

$C_{2}=2\ \mu F$

$C_{3}=2\ \mu F$

$C_{4}=2\ \mu F$

$C_{5}=4\ \mu F$

(a). We need to calculate the equivalent capacitance

According to diagram,

The equivalent capacitance between A and B is 2μF. Because the potential shifted A to D and B to E.

So, The equivalent capacitance will be 2 μF.

(b). We need to calculate the maximum charge

Using formula of charge

$Q=CV$

Where, C = capacitance

V = potential

Put the value into the formula

$Q=2\times5$

$Q=10\ C$

(c). We need to calculate the total energy stored in the network

Using formula of store energy

$E=\dfrac{1}{2}CV^2$

Put the value into the formula

$E=\dfrac{1}{2}\times2\times5^2$

$E=25\ J$

Hence, (a). The equivalent capacitance is 2 μF.

(b). The maximum charge is 10 C.

(c). The total energy stored in the network is 25 J.

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Topic : capacitance

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