In the figure given below, find the area of the shaded region ( use π =3.14
Answers
Answer:
Hello mate
Here is your answer
1st we calculate the diagonal of the rectangle
So, diagonal of rectangle = BD
( BD) ^2 =( AB)^2+(AD) ^2
= 64 cm^2+ 36 cm.^2
= 100 cm^2
=> BD =√ 100cm
= 10 cm
So, diagonal = 10cm
Now as diagonal passes through the center, it is forming the diameter of the circle
So radius = Diameter /2
= 10/2 = 5 cm
Area of circle =2πr^2
= 2*3.14*25 cm ^2
= 157cm^2
Now Area of rectangle = Length *Breadth
= 6*8 cm^2
= 48 cm^2
So, Area of shaded region
= Area of circle -Area of rectangle
=( 157-48)cm^2
= 109 cm^2
hope it helps
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area of shaded region = Ar of circle- Ar of rectangle
Area of circle = πr^2
and area of rectangle = Length X breadth
= 6x8= 48cm^2
now .., length of one of the diagonal BD =?
by Pythagoras
BD= √ AB^2 + AD ^2
BD =√ 36+48
BD = √ 84
BD = 9.16
Now, radius of circle = 4.58cm
so ...area of circle
= 3.14 x 4.58 x 4.58cm sq.
= 65.86 cm sq.
Ar of shaded region= 65.56 - 48 cm sq.
= 17.86 cm sq..
this is the required answer .
hope its helpful
cheers ..!