in the figure given below ,OL isperpendicular to ab and om is perpendicular to AC such that ol is equal to oM is angle olb congruent to angle omb
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In ∆OLB AND ∆OMB,
(Side) OL=OM ( Given )
(Angle) angle L = angle M ( Both are 90° as Given OL and OM are perpendiculars to AB & BC)
(Side) BO=BO (Common)
Therefore, By S-A-S congruency we can say that ∆OLB is congruent to ∆OMB
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Step-by-step explanation:
In triangles OLB and OMB,
(angle)BLO=angleOMB (each 90)
OB= OB (common side)
OL=OM (given)
thus triangles OLB and OMB are congruent by RHS congruence criteria.
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