Question

in the figure given below , PA and PB are tangents to the circle drawn from an external point P .CD is a third tangent touching the circle at Q . if PB = 10 cm and CQ = 2cm what is the length of PC

Answer 1

PA = PB = 10 cm (tangents from an external point to a circle are equal) 

CQ = CA = 2 cm  

PC = PA – AC 

= 10 – 2 

= 8 cm 

Answer 2

Answer:18cm

Step-by-step explanation:

PA=PB=12 cm____1

QC=AC=3 cm_____2

QD=BD=3 cm_______3

To find: PC+PD

(PA-AC)+(PB-BD)___from 1,2,3

9+9=18 cm