In the figure, given below, PO bisects angle P and SO bisects angle S of parallelogram PQRS. Prove that: ∠POS =90°
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here, the figure is of rectangle.
i.e,
now,
let us take 2 lines.
PR and QS
as we know that rectangle has parallel lines in 2 sides here, P,Q,R,S=90°
so,when we take lines intersecting point, we get o
therefore we can hence note that angle POS is 90°
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