Question

In the figure given below, PT is a tangent to the circle with centre O and PQ is the diameter through P. PR and QR are chords of the circle . If angle RPT= 40 degree, then find angle PQR.

​

Answer 1

_/^50 + _/^48=_/^99
_/^50 + _/^48=_/^99
_/^50 + _/^48=_/^99
_/^50 + _/^48=_/^99
_/^50 + _/^48=_/^99
Yes this is the answer !!!