Question

in the figure given below, ray OP stands on line AB such that AOP = (2x + 30)° and BOP = (3x)°. find the value of x​

Answer 1

Answer:

[x =34]

Step-by-step explanation:

The figure will be as shown,

Given, angle AOC = (2x - 10°) and angle BOC = (3x + 20°) also, AOB is a straight

line.

The sum of two angles on a straight line is 180°.

As, AOB is a straight line;

=> angle AOC + angle BOC = 180°

=> (2x-10) + (3x+20) = 180

=> 2x - 10 + 3x + 20 = 180

=> 5x + 10 = 180

=> 5x = 180 - 10

=> 5x = 170

=> x = 170/5

=> x = 34

Answer 2

Answer:

First if all,

1. Since OP is a Ray which lies on line AB so it is perpendicular (90) to the line.
2. Hence, AOP becomes 90° and BOP also becomes 90°.
3. Now, since AOP and BOP is 180° i.e AOP+ BOP= 180°( 90°+90°)
4. Hence, 2x+3x+30°= 180°
5. 5x+30°=180°
6. 5x=180°-30°
7. 5x= 150°
8. x= 150°÷5
9. x= 30°