Question

In the figure given below, show that length AH>AB+BC + CD.​

Answer 1

Answer:

AH=AB+BC+CD+DE+EF+FG+GH

AH=AB+BC+CD+DE+EF+FG+GH⇒AB+BC+CD is a part of AH

AH=AB+BC+CD+DE+EF+FG+GH⇒AB+BC+CD is a part of AHAccording to Euclid's fifth axiom the whole thing is greater then a part

AH=AB+BC+CD+DE+EF+FG+GH⇒AB+BC+CD is a part of AHAccording to Euclid's fifth axiom the whole thing is greater then a part∴AH>AB+BC+CD

Step-by-step explanation:

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