In the figure given below, ST||QR and angle P =50°, angle Q =60°, find :
a. angle PST
b. angle PTS
c. angle QST
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angle PST = 60°
angle PTS = 70°
angle QST = 120°
Solution
Sum of interior angle of triangle = 180°
P = 50° ; Q = 60°
R = 180 - 50 - 60
R = 70°
In parallel line Corresponding angles are equal and co- interior angles add upto 180°
Since ST||QR
Corresponding angles are equal
Angle Q = angle PST = 60°
Angle R = angle PTS = 70°
co- interior angles add upto 180°
angle Q + angle QST = 180°
angle QST = 180 - 60 = 120°
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