In the figure,given below ,the median BD bisect angle B . Prove that AB=BC....
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Step-by-step explanation:
IN ΔABD AND ΔACD
BD IS A MEDIAN
∴ ∠DBC = ∠DBA
∴ AD = DC
NOW IN ΔABD AND ΔDBC
∠DBC = ∠DBA(PROVED ABOVE)
AD = AC(PROVED ABOVE)
BD = BD (COMMON)
BY SAS CRITERIA
ΔABD ≅ ΔBDC
mili1978pikugm65:
and how AD=AC
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