Question

In the figure given BL perpendicular to AC, MC perpendicular to LN, AL=CN and BL=CM.Prove that triangle ABC congruent to triangle NML​

Answer 1

Step-by-step explanation:

To prove the the triangles congruent first we have to prove their parts as congruent

so fisrstly in

ALB and NCM

AL = CN

BL = MC

<ALB = <MCN = 90 deg

ALB = NCM by SAS

and let <A = <N = x (by cpct)

now other pairs of triangles

in MCL and BLC

CL=CL (common side )

BL = MC

< BLC = < MCL = 90deg

MCL = BLC (by SAS)

now let <C =< L = y (by cpct)

now lets assume AL = CN = z cm

and side CL = w cm

now AC = LN = ( z + w ) cm

now in ABC and NLM

< N = <A

<C = < L

AC = LN

So ABC = NLM ( by ASA ) Answer