In the figure, given that l∥m and t is a transversal. If ∠ 1 = (110° – x) and ∠ 5 = 4x, then the
measures of ∠ 1 and ∠ 5 are :
(a) 55°, 55°
(b) 22°, 88°
(c) 55°, 88°
(d) 88°, 88°
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Answer:
(d) 88°, 88°
Step-by-step explanation:
angle 5 =angle 3 (alternate interior angle)
4x=angle 3
angle 1=angle 3 (vertical opposiye angle)
110°-x = 4x
110˚= 4x+x
110°= 5x
110°/5= x
22°= x
then, angle 1 = 110°-x= 110°- 22°= 88°
angle 5= 4x = 4* 22°= 88°
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