In the figure given , what is the measure of angle ACD?
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him dear here's ur answer
- first just join AD
- now we get a cyclic quadrilateral.
- since the opposite angles of a cyclic quadrilateral is 180 degree.
- now take the chord BC, angle A = angle=D (angles in the same segment is equal.)
- now mark point of the intersection of Lines AC And BD as 'o'.
- angle DOC = 75 degree. (VOA are equal)
- now finally angle ACD =80degree. (by applying ASP of triangle, 75+25=100,180-100=80)
- hope it works for you........
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