In the figure, if AB = AC, prove that BE = CE.
Plz solve as soon as possible
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Since tangents from an exterior point to a circle are equal
in length.
AD=AF[Tangents from A]−−−−(i)
BD=BE[Tangents from B]−−−−(ii)
CE=CF[Tangents from C]−−−−(iii)
Now,
AB=AC [Given]
⇒AB−AD=AC−AD [ Subtracting AD from both sides ]
⇒AB−AD=AC−AF [ using (i) ]
⇒BD=CF
⇒BE=CF [ using (ii) ]
⇒BE=CE [ using (iii) ]
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