Question

In the figure if AB = AD and AB bisects angleA. Show that triangleABC ≈ triangleADC.

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Answer 1

Step-by-step explanation:

Proof : In ∆ABC & ∆ ADC, we have :

AB = AD. (given)

ang. DAC = ang. BAC. (given)

AC = AC. (common)

Therefore , ∆ABC cong. ∆ADC (SAS rule)

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Answer 2

Step-by-step explanation:

IN triangle ABC and Triangle ADC

                  ab = ad              (given)

             /_dac = /_cab        (bisected)(halves of the same quantity are equal)

                  ac = ac              (common)

          Δ ABC ≅ ΔADC       (SAS congruency)

           

HENCE PROVED

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