Question

In the figure, if AB=CD and qngleAOB=90° find angle COD
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Answer 1

$In \: given \: figure \: \\ \\ AB=AC$

In figure O is the center of circle and Point A,B,C and D on circumference of circle .

Then OA, OB ,OC and OD is the radius of circle

In ΔAOB and COD

AB=AC (given)

OA=OC (Radius)

OB=OD (Radius)

∴ΔAOB≅COD

∴∠AOB=∠COD=90°

Given (∠AOB=90° )

Then (∠COD=90°)

Answer 2

Answer:

$\sf \red{in \: given \: figure}$

AB=AC

AB=AC

AB=AC

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circle

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circleIn ΔAOB and COD

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circleIn ΔAOB and CODAB=AC (given)

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circleIn ΔAOB and CODAB=AC (given)OA=OC (Radius)

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circleIn ΔAOB and CODAB=AC (given)OA=OC (Radius)OB=OD (Radius)

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circleIn ΔAOB and CODAB=AC (given)OA=OC (Radius)OB=OD (Radius)∴ΔAOB≅COD

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circleIn ΔAOB and CODAB=AC (given)OA=OC (Radius)OB=OD (Radius)∴ΔAOB≅COD∴∠AOB=∠COD=90°

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circleIn ΔAOB and CODAB=AC (given)OA=OC (Radius)OB=OD (Radius)∴ΔAOB≅COD∴∠AOB=∠COD=90°Given (∠AOB=90° )

AB=AC In figure O is the center of circle and Point A,B,C and D on circumference of circle .Then OA, OB ,OC and OD is the radius of circleIn ΔAOB and CODAB=AC (given)OA=OC (Radius)OB=OD (Radius)∴ΔAOB≅COD∴∠AOB=∠COD=90°Given (∠AOB=90° )Then (∠COD=90°)

Step-by-step explanation:

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