In the figure, if AB||CD,CD||RD and x:y=5:4, find z
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summaiyashabre:
It's not RD it's EF
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x + y = 180 ( co. interior angle )
⇒ 5n + 4n = 180
⇒ 9 n = 180
∴ n = 20
∴ x = 20 * 5 = 100
x = z (alternate angle )
∴ z = 100
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Answered by
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hey mate [^-^]
solution :- In the figure, AB is parallel to EF,
Therefore, x+y = 180 (co-interior angles are supplementary)
Let x = 5a
Let y = 4a
x+y = 180
5a+4a = 180
9a = 180
a = 180/9 = 20 degrees
Therefore, x = 5a = 100 degrees
Since AB is parallel to CD,
x = z = 100 (alternate interior angles are equal)
Hope this helps!
solution :- In the figure, AB is parallel to EF,
Therefore, x+y = 180 (co-interior angles are supplementary)
Let x = 5a
Let y = 4a
x+y = 180
5a+4a = 180
9a = 180
a = 180/9 = 20 degrees
Therefore, x = 5a = 100 degrees
Since AB is parallel to CD,
x = z = 100 (alternate interior angles are equal)
Hope this helps!
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