Question

In the figure, if AB11 CD, find X and y​

Answer 1

Step-by-step explanation:

Let us draw a line EF parallel to the lines AB and CD.

Then ∠BPF=∠ABP=48

o

[ alternate angle].......(1).

Also, ∠CPF=∠PCD=24

o

[ alternate angle]......(2).

Now

∠BPC=∠BPF+∠CPF=48

o

+24

o

=72

o

.

Then x=360

o

−72

o

=288

o

.

Answer 2

Answer:

${.5 { \frac{5.22 \cot(e \cot( \alpha 0 < - 2 + \div \leqslant < 2350 { < 2 < 2 < 6. < )32 < \sqrt{522 < } }^{2} ) ) }{?} }^{?} }^{2} x5x3 = ))3 \sqrt{?} \times \frac{?}{?} 6223 \sqrt{2.y.5)2 {3 { \frac{33 \div 1 \div - 5 \times \times < 4 > 12\% \times \frac{?}{?} }{?} }^{2} }^{?} } \sec(ujj)$