In the figure, if Δ ABC ≅Δ ECD and BC = AE, then prove that Δ ABC ≅Δ CEA
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Step-by-step explanation:
In ΔACB and ΔECD
It is given that
AC=CE
and BC=CD
∠ACB=∠DCE (are vertically opposite angles)
Hence ,
ΔACB≅ΔECD (SAS Axiom)
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