In the figure,if AC=BD then prove that AB=CD
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Answer:
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Answered by
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Solution:
Given, AC = BD......(1)
From the figure,
AC = AB + BC &
BD = BC + CD
On putting these values in eq 1,
⇒ AB + BC = BC + CD
According to Euclid’s axiom, when equals are subtracted from equals, remainders are also equal.
On Subtracting BC from both sides,
AB + BC – BC = BC + CD – BC
AB = CD [ by axiom 3 of Euclid]
=========================================================
Hope this will help you....
Given, AC = BD......(1)
From the figure,
AC = AB + BC &
BD = BC + CD
On putting these values in eq 1,
⇒ AB + BC = BC + CD
According to Euclid’s axiom, when equals are subtracted from equals, remainders are also equal.
On Subtracting BC from both sides,
AB + BC – BC = BC + CD – BC
AB = CD [ by axiom 3 of Euclid]
=========================================================
Hope this will help you....
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