In the figure if AD=BD=CD PROVE THAT ANGLE BAC IS RIGHT ANGLE
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Where is the figure?
abhinanddsunil:
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Let angle DAB= Angle 1
Angle DBA= Angle 2
Angle DAC= Angle 3
Angle DCA= Angle 4
Angle 1 = Angle 2 (Angles opp. To equal angles are equal) ....(1)
Similarly
Angle 3 = Angle 4 ....(2)
Adding (1) and (2)
Angle 1 + Angle 3 = Angle 2 + Angle 4 ....(3)
Let Angle 1 + Angle 3 = Angle 5 ....(4)
Therefore Angle 5 + Angle 4 + Angle 2 = 180
Substituting values of the above equation from (3) and (4)
Angle 1 + Angle 2 + Angle 1 + Angle 2 = 180
2(Angle 1 + Angle 2) = 180
Angle 1 + Angle 2 = 180
Angle BAC = 90
Hence proved
Angle DBA= Angle 2
Angle DAC= Angle 3
Angle DCA= Angle 4
Angle 1 = Angle 2 (Angles opp. To equal angles are equal) ....(1)
Similarly
Angle 3 = Angle 4 ....(2)
Adding (1) and (2)
Angle 1 + Angle 3 = Angle 2 + Angle 4 ....(3)
Let Angle 1 + Angle 3 = Angle 5 ....(4)
Therefore Angle 5 + Angle 4 + Angle 2 = 180
Substituting values of the above equation from (3) and (4)
Angle 1 + Angle 2 + Angle 1 + Angle 2 = 180
2(Angle 1 + Angle 2) = 180
Angle 1 + Angle 2 = 180
Angle BAC = 90
Hence proved
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