Question

In the figure, if AE=14cm, AC=13 cm, BC=5 cm find the value of tan tan theta​

Answer 1

Step-by-step explanation:

plz mention which angle's theta should be found....

Answer 2

Answer:

Step-by-step explanation:

AE=14

AE= AD+DE

AE=BC+DE(AD=BC since all sides of square are equal)

14=5+DE

14-5=DE

9=DE

In triangle CDA

BC=AD=5

CA=13      by Pythagoras theorem:

$h^2=p^2+b^2\\(13)^2=p^2+(5)^2\\169=p^2+25\\p^2=169-25\\p^2=144\\p=\sqrt{144}\\\p=12$

AB=12

DE=9

In triangle DEC    By Pythagoras theorem:

$h^2=p^2+b^2\\h^2=(9)^2+(12)^2\\h^2=81+144\\h=\sqrt{225}\\h=15$

tan theta = $\frac{p}{b}=\frac{9}{12}=\frac{3}{4}$