Question

in the figure if angle 1 is equal to 30 degree find angle 2 and angle 3.​

Answer 1

Answer:

angle 2 and angle 3 are equal

angle 1 + angle 2 + angle 3 = 180⁰

30+x+x = 180⁰

x + x = 180-30=150

2x = 150

x = 150÷2

x = 75⁰

angle 2 = 75⁰

angle 3 = 75⁰

Answer 2

Given: Angle 1 in the triangle is 30 degree.

Need to find: Angle 2 & angle 3.

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❍ Let's consider Angle 2 and angle 3 of triangle be x.

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As we know that,

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$\begin{gathered}\star\:{\underline{\boxed{\frak{Sum \: of \: all \: the \: angles_{\:(triangle)} = 180^{\circ}}}}}\\\\\\ \bf{\dag}\:{\underline{\frak{Putting\:given\:values\:in\:formula,}}}\\\\\\ :\implies\sf 30^{\circ} + x + x = 180^{\circ}\\ \\ \\ :\implies\sf 2x = 180 ^{\circ} - 30 ^{\circ} \\\\\\ :\implies\sf 2x = 150 ^{\circ}\\\\\\ :\implies\sf x = \dfrac{150}{2}\\\\\\ :\implies{\underline{\boxed{\frak{\purple{x = 75^{\circ}}}}}}\:\bigstar\\\\\end{gathered}$

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Therefore,

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Angle 2, x = 75°

Angle 3, x = 75°

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$\therefore\:{\underline{\sf{Hence,\:Angle \: 2 \: and \: angle \: 3 \: are \: \bf{75^{\circ}}\: \sf{respectively}.}}}$

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$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(3.8,0.3){ \bf {30}^{\circ} }\put(4.5,0){\qbezier(0,0)(0,0.5)(0.3,0.3)}\put(2.7,3.2){ \bf A }\put(0.1,0){ \bf B }\put(5.4,0){ \bf C }\end{picture}$