Question

in the figure, if angle AOC+ANGLE BOD=70°, find angle COD​

Answer 1

Step-by-step explanation:

ANSWER

ANSWER16=4+3(t+2)

ANSWER16=4+3(t+2)⇒16−4=3(t+2)

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12⇒(t+2)=

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12⇒(t+2)= 3

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12⇒(t+2)= 312

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12⇒(t+2)= 312

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12⇒(t+2)= 312 =4

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12⇒(t+2)= 312 =4⇒t+2=4

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12⇒(t+2)= 312 =4⇒t+2=4⇒t=4−2=2

ANSWER16=4+3(t+2)⇒16−4=3(t+2)⇒3(t+2)=12⇒(t+2)= 312 =4⇒t+2=4⇒t=4−2=2∴t=2

Answer 2

Answer:

ANGLE AOC + ANGLE BOD+ ANGLE COD=180 {LINEAR PAIR}

30+40+ANGLE COD=180

70+ANGLE COD=180

ANGLE COD=180-70

ANGLE COD=110

Step-by-step explanation: