in the figure if AOB =125 degree then find COD
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Answered by
30
Thank you for asking this question. Here is your answer:
The quadrilateral angle's circle meet at the point of the supplementary angles and that is at the center.
ABCD will meet at a point where it won't cut it but it will just pass it, and that would be the center at O.
∠AOB + ∠COD = 180°
125° + ∠COD = 180°
∠COD = 180° - 125°
∠COD = 55°
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Answered by
10
COD = 55°
please make me a brainlist answer for the question
please make me a brainlist answer for the question
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