in the figure, if B1, B2, B3,...... and A1, A2, A3,...... has been marked at equal distance. in what ratio C divides AB?
Answers
C divides AB in the ratio 8:5
Step-by-step explanation:
As shown in the attached figure
If we draw lines parallel to from points and respectively
Also if we draw lines parallel to from points and respectively
Then we can clearly see that CB contains 5 parts and CA contains 8 parts
Therefore, point C divides AB in the ratio 8:5[/tex]
Hope this answer is helpful.
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Given : B1, B2, B3,. and A1,A2, A3,. . have been marked at equal distances
To Find : C divides AB in what ratio
Solution:
in Δ B₅CB & Δ A₈CA
∠B₅CB = ∠ A₈CA( vertically opposite angles)
∠CBB₅ = ∠CAA₈ ( alternate angles)
∠CB₅B = ∠CA₈A ( alternate angles)
Δ B₅CB ≈ Δ A₈CA (AAA)
Similar triangles corresponding angles are congruent and the corresponding sides are proportional
=> BC/AC = BB₅ /AA₈
B1, B2, B3,. and A1,A2, A3,. . have been marked at equal distances
=>BB₅ = 5x
AA₈ = 8x
BC/AC = 5x / 8x
=> BC/AC = 5/8
=> AC/BC = 8/5
C divided AB in 8 : 5 ratio
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