Math, asked by Akankshyasahoo804, 6 months ago

In the figure, if B1, B2, B3,...... and A1,A2, A3,..... have been marked at
equal distances. In what ratio C divides AB?


plz answer this question

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Answers

Answered by cheshireduke0
281

Answer: 8:5

Step-by-step explanation:

Since we've been given in the question that b1,b2,b3,.... and a1,a2,a3 are marked at equal distances it means that to obtain the ratio we divide both sides 8 and 5

--> AA8 / BB5 = 8/5

which gives ratio 8:5

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Answered by amitnrw
23

Given : B1, B2, B3,.  and A1,A2, A3,. . have been marked at equal distances

To Find :  C divides AB in what ratio  

Solution:

in Δ B₅CB  & Δ A₈CA

∠B₅CB = ∠ A₈CA( vertically opposite angles)

∠CBB₅ = ∠CAA₈ ( alternate angles)

∠CB₅B   = ∠CA₈A  ( alternate angles)

Δ B₅CB  ≈ Δ A₈CA  (AAA)

Similar triangles corresponding angles are congruent and the corresponding sides are proportional

=> BC/AC  = BB₅ /AA₈

B1, B2, B3,.  and A1,A2, A3,. . have been marked at equal distances

=>BB₅   = 5x

  AA₈ = 8x

BC/AC = 5x / 8x

=> BC/AC = 5/8

=> AC/BC = 8/5

C divided AB in 8 : 5 ratio

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