Question

. In the figure, if DE || OB and EF || BC, then prove that DF || OC.​

Answer 1

Step-by-step explanation:

DE║OB then by B.P.T theorem

AE/EB=AD/DO          .................1

EF║BC then by B.P.T theorem

AE/EB=AF/FC           ..................2

BY EQ. 1 AND 2

AF/FC=AD/DO

THEN BY CONVERSE OF B.P.T THEOREM  

DF║OC

Answer 2

$\huge \mathcal {\fcolorbox{red}{gray}{\green{A}\pink{N}\orange{S}\purple{W}\red{E}\blue{R}{!}}}$

if DE║OB then by B.P.T theorem

AE/EB=AD/DO          .................1

EF║BC then by B.P.T theorem

AE/EB=AF/FC           ..................2

BY EQ. 1 AND 2

AF/FC=AD/DO

THEN BY CONVERSE OF B.P.T THEOREM 

DF║OC

HOPE SO IT WILL HELP.....