Question

in the figure if DE parallel to BC and AD/DB = 5/4 then find ratios of areas of triangle ADE and triangle ABC​

Answer 1

Answer:

In △ABC, we have

                        DE||BC

⇒ ∠ADE=∠ABC and ∠AED=∠ACB             [Corresponding angles]

Thus, in triangles ADE and ABC, we have

         ∠A=∠A              [Common]

         ∠ADE=∠ABC

and,  ∠AED=∠ACB

∴    △AED∼△ABC         [By AAA similarity]

⇒ ABAD=BCDE

We have,

      DBAD=45

⇒ ADDB=54

⇒ ADDB+1=54+1

⇒ ADDB+AD=59

⇒ ADAB=59⇒ABAD=95

∴   

Explanation:

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