In the figure if lines AB and CD are parallel lines, ∠ABE = 70 o and ∠BED=30 o ,then find the value of ∠CDE.
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if AB || CD, then ∠ABE = ∠CPE
(P is the point of intersection of line BE and CD)
and, ∠BED = 30° (given)
hence by property of triangle,
∠DPE + ∠PED + ∠PDE = 180°
180°-70° + 30° + x = 180°
x = 70 - 30
x = 40°
∠CDE = 40°
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